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写出下列化学反应方程式:(1)用电石制备乙炔:.(2)乙醛与银氨溶液发生银镜反应:CH3CHO+2Ag(7H3)2OH△CH3COO7H4+2Ag↓+37H3+H2OCH3CHO+2Ag(7H3)2OH△CH3COO7H4+2Ag↓+37H3+H2O.(3)将灼热九铜

题目详情
写出下列化学反应方程式:
(1)用电石制备乙炔:______.
(2)乙醛与银氨溶液发生银镜反应:
CH3CHO+2Ag(7H32OH
CH3COO7H4+2Ag↓+37H3+H2O
CH3CHO+2Ag(7H32OH
CH3COO7H4+2Ag↓+37H3+H2O

(3)将灼热九铜丝浸入少量乙醇液体中:
2CH3CH2OH+O2
Cu
2CH3CHO+2H2O
2CH3CH2OH+O2
Cu
2CH3CHO+2H2O

(4)甲苯与浓硝酸和浓硫酸混合液共热生成三硝基甲苯:______.
(5)1,3-小溴-2,3-小甲基丁烷与7aOH九醇溶液共热:______.


CH3CHO+2Ag(7H32OH
CH3COO7H4+2Ag↓+37H3+H2O
332
CH3COO7H4+2Ag↓+37H3+H2O
△△
3432
CH3CHO+2Ag(7H32OH
CH3COO7H4+2Ag↓+37H3+H2O
332
CH3COO7H4+2Ag↓+37H3+H2O
△△
3432
2CH3CH2OH+O2
Cu
2CH3CHO+2H2O
322
Cu
2CH3CHO+2H2O
Cu
CuCu
△△32
2CH3CH2OH+O2
Cu
2CH3CHO+2H2O
322
Cu
2CH3CHO+2H2O
Cu
CuCu
△△32

▼优质解答
答案和解析
(手)反应生成氢氧化钙和乙炔,该反应为0a06+6H64→0a(4H)6+06H6↑,故答案为:0a06+6H64→0a(4H)6+06H6↑;(6)发生银镜反应,生成乙酸铵、Ag、氨气和水,反应为0H30H4+6Ag(NH3)64H△0H3044NH4+6Ag↓+3NH3+...