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cis45°-cos60°/cos45°+sin30°+2√(sin45°-1）²是多少,
题目详情
cis45°-cos60°/cos45°+sin30°+2√(sin45°-1）² 是多少,
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答案和解析
cis45°是不是应该是cos45°
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cos45°-cos60°/cos45°+sin30°+2√(sin45°-1）²
= √2/2 - (1/2) / √2/2 + 1/2 +2√(√2/2 -1)²
= √2/2 - √2/2 + 1/2 +2(√2/2 -1)
= 1/2 + √2 -2
= √2 -3/2
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cos45°-cos60°/cos45°+sin30°+2√(sin45°-1）²
= √2/2 - (1/2) / √2/2 + 1/2 +2√(√2/2 -1)²
= √2/2 - √2/2 + 1/2 +2(√2/2 -1)
= 1/2 + √2 -2
= √2 -3/2
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