早教吧作业答案频道 -->英语-->
3第二部分跪求翻译实验部分第一部分第三段TodeveloptheunderstandingofMOF-basedmaterialsforSO2removal,weexaminedSO2adsorptioninaprototypicalmetalorganicframeworkM(bdc)(ted)0.5[M=Ni,Zn;H2bdc=1,4-benzenedicarbo
题目详情
3第二部分 跪求翻译 实验部分
第一部分第三段
To develop the understanding of MOF-based materials for SO2 removal, we examined SO2 adsorption in a prototypical metal organic framework M(bdc)(ted)0.5 [M= Ni, Zn; H2bdc =1,4-benzenedicarboxylic; ted = triethylenediamine] and characterized the guest-host interaction by in-situ infrared spectroscopy and isotherm measurements. Our results show that high SO2 capacity uptake can be achieved even when using coordinatively saturated MOFs M(bdc)(ted)0.5, at levels up to9.97 mmol/g at room temperature and 1.13 bar. Combining infrared spectroscopy and first principles calculations, the adsorption mechanism of SO2 within this class of MOFs is explored. Multipoint interactions between SO2 molecules and MOFs are found as possible binding sites within the frameworks: SO2 interacting i) with the O site of the paddlewheel building units through its sulfur atom, and ii) with the C-Hx groups on the organic linkers through its oxygen atoms.
第二部分 实验
Synthesis: A mixture of nickel (II) chloride hexahydrate (0.107 g, 0.45 mmol), H2bdc (0.060 g, 0.36 mmol), ted (0.033 g, 0.29 mmol) and 15 ml of DMF were transferred to Teflonlined autoclave and heated at 120 °C for 2 days. Green crystalline powder of Ni(bdc)(ted)0.5 was isolated by filtering and washed three times with 10 ml of DMF. (Yield: 83.8% based on the metal) Then the sample was heated at 120 °C again under a flow of dry N2 for one day to remove the guest DMF molecules.
第一部分第三段
To develop the understanding of MOF-based materials for SO2 removal, we examined SO2 adsorption in a prototypical metal organic framework M(bdc)(ted)0.5 [M= Ni, Zn; H2bdc =1,4-benzenedicarboxylic; ted = triethylenediamine] and characterized the guest-host interaction by in-situ infrared spectroscopy and isotherm measurements. Our results show that high SO2 capacity uptake can be achieved even when using coordinatively saturated MOFs M(bdc)(ted)0.5, at levels up to9.97 mmol/g at room temperature and 1.13 bar. Combining infrared spectroscopy and first principles calculations, the adsorption mechanism of SO2 within this class of MOFs is explored. Multipoint interactions between SO2 molecules and MOFs are found as possible binding sites within the frameworks: SO2 interacting i) with the O site of the paddlewheel building units through its sulfur atom, and ii) with the C-Hx groups on the organic linkers through its oxygen atoms.
第二部分 实验
Synthesis: A mixture of nickel (II) chloride hexahydrate (0.107 g, 0.45 mmol), H2bdc (0.060 g, 0.36 mmol), ted (0.033 g, 0.29 mmol) and 15 ml of DMF were transferred to Teflonlined autoclave and heated at 120 °C for 2 days. Green crystalline powder of Ni(bdc)(ted)0.5 was isolated by filtering and washed three times with 10 ml of DMF. (Yield: 83.8% based on the metal) Then the sample was heated at 120 °C again under a flow of dry N2 for one day to remove the guest DMF molecules.
▼优质解答
答案和解析
3 为了更好地了解以MOF为基准的材料脱除SO2,我们研究了一个原型金属有机骨架对SO2的吸收.该金属有机骨架为M(bec)(ted)0.5[ M = Ni,Zn;H2bdc=1,4 -苯二羧酸,ted=三乙撑二胺] 并由现场制备红外光谱的宾体-主体相互作用和等温测定来表征.我们的研究结果表明,使用配位饱和的MOFs M(boc)(ted)0.5,在室温和1.13bar的压力下,吸收SO2的能力可以高达9.97毫摩尔/克.结合红外光谱和原理计算,探讨了SO2在这类材料中的吸附机理.发现SO2分子和MOFs 之间的多点相互作用,在骨架中可能结合位点:SO2的相互作用有i)通过硫原子与轮浆构建单元上的O位相互作用,ii)通过氧原子上的有机连接体与G-Hx基团相互作用.
合成:将氯化镍(II)六水合物(0.107 g,0.45 mmol),H2bdc (0.060 g,0.36 mmol),三乙撑二胺(0.033克,0.29毫摩尔)和15ml 的DMF 的混合物转移到聚四佛乙烯连接的高压釜中,在120°C下加热2天.过滤分离绿色结晶粉末的Ni(bdc)(ted)0.5. 用10 ml DMF 洗三次.(产率:83.8%,以金属Ni为准)然后将样品在干燥氮气流下在120C°加热到一天, 以除去客体DMF分子.
合成:将氯化镍(II)六水合物(0.107 g,0.45 mmol),H2bdc (0.060 g,0.36 mmol),三乙撑二胺(0.033克,0.29毫摩尔)和15ml 的DMF 的混合物转移到聚四佛乙烯连接的高压釜中,在120°C下加热2天.过滤分离绿色结晶粉末的Ni(bdc)(ted)0.5. 用10 ml DMF 洗三次.(产率:83.8%,以金属Ni为准)然后将样品在干燥氮气流下在120C°加热到一天, 以除去客体DMF分子.
看了 3第二部分跪求翻译实验部分第...的网友还看了以下:
elevenhellothesehen中e的发音有几种答案上是4种,我搞不清的是hello和hen 2020-05-12 …
C.A.S.E翻译C.A.S.E如何翻译?列句:Reference(s):C.A.S.E.chap 2020-05-12 …
A、B、C、D、E五人参加抢答比赛,每题都有人回答,答对一题的一分,答错一题得-1分,比赛结束,五 2020-06-24 …
①紫黑色固体A在受热条件下分解生成固体B、C和气体D②无色液体E在一定条件下也可以分解生成一种鱼类 2020-06-26 …
如图,在△ABC中,AB=AC,cosB=1/3,BC=2,点D,E,F分别在AC,AB,BC边上 2020-06-27 …
在匀强电场中E=Uq,U是电势差,E是什么?电场强度么==.可是在E=2分之1mv方—E=2分之1 2020-07-16 …
I.果蝇的基因A、a控制翅型,E、e控制眼色,两对基因分别位于常染色体和性染色体上,且基因A具有纯合 2020-12-07 …
I.果蝇的基因A、a控制翅型,E、e控制眼色,两对基因分别位于常染色体和性染色体上,且基因A具有纯合 2020-12-07 …
微积分分部积分有e时的特殊情况(e微分还是e)要怎么简短的证明∫(x^n)(e^x)dx=[(x^n 2020-12-12 …
函数的连续及判断(e^x分之1)-e^-x分之1)/(e^x分之1+e-x分之1)=(e^x分之2) 2020-12-17 …