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当x=1998,y=1949时,求x^4-y^4/x^2-2xy+y^2×y-x/x^2+y^2的值
题目详情
当x=1998,y=1949时,求x^4-y^4/x^2-2xy+y^2×y-x/x^2+y^2的值
▼优质解答
答案和解析
=(x²+y²)(x+y)(x-y)/(x-y)²×[-(x-y)]/(x²+y²)]
=-(x+y)/(x-y)
=-(1998+1949)/(1998-1949)
=-3947/49
=-(x+y)/(x-y)
=-(1998+1949)/(1998-1949)
=-3947/49
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