C#编写程序证明斐波那契数列的数列前后项的比值无限接近0.618

Question

C#编写程序 证明斐波那契数列的数列前后项的比值无限接近0.618

Answer 1

static void Main(string[] args)
{
double i = 1;
double j = 1;
double n = 1;
while (true)
{
Console.WriteLine("a{0}:a{1}={2}:{3}={4}",n,n + 1,i,j,i / j);
double temp = j;
j += i;
i = temp;
n++;
System.Threading.Thread.Sleep(100);
}
}