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有关数列的求和:Sn=1+1/(1+2)+1/(1+2+3)+……+1/(1+2+3+……n)
题目详情
有关数列的
求和:
Sn=1+1/(1+2)+1/(1+2+3)+……+1/(1+2+3+……n)
求和:
Sn=1+1/(1+2)+1/(1+2+3)+……+1/(1+2+3+……n)
▼优质解答
答案和解析
Sn=1+1/(1+2)+1/(1+2+3)+……+1/(1+2+3+……n)
=2/1×2+2/2×3+2/3×4+……+2/n(n+1)
=2{(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+[1/n-1/(n+1)]}
=2[1-1/(n+1)]
=2-2/(n+1)
=2/1×2+2/2×3+2/3×4+……+2/n(n+1)
=2{(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+[1/n-1/(n+1)]}
=2[1-1/(n+1)]
=2-2/(n+1)
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