matlab常微分数值解是指原函数么有这么一道题：dy/dx-2x=2x/y;y(1)=0如何做?y=dsolve('Dy-2x-2x/y','是y=dsolve('Dy-2x-2x/y',',y(1)=0','x')漏了问的是数值解是啥,应该不是原函数吧

Question

matlab 常微分数值解是指原函数么 有这么一道题：dy/dx-2x=2x/y;y(1)=0 如何做?y=dsolve('Dy-2x-2x/y','
是y=dsolve('Dy-2x-2x/y',',y(1)=0','x')漏了
问的是数值解是啥,应该不是原函数吧

Answer 1

请您学会help
例如 输入 help dsolve
例子里面有一个
x = dsolve('Dx = -a*x','x(0) = 1','s') returns

x = 1/exp(a*s)
所以应该是dsolve('Dy-2*x-2*x/y','y(1)=0',‘x’)