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计算:(1)[50−(79−1112+16)×(−6)2]÷(−7)2(2)−32×1.22÷0.32+(−13)2×(−3)3÷(−1)2007.
题目详情
计算:
(1)[50−(
−
+
)×(−6)2]÷(−7)2
(2)−32×1.22÷0.32+(−
)2×(−3)3÷(−1)2007.
(1)[50−(
7 |
9 |
11 |
12 |
1 |
6 |
(2)−32×1.22÷0.32+(−
1 |
3 |
▼优质解答
答案和解析
(1)[50−(
−
+
)×(−6)2]÷(−7)2
=[50-(28-33+6)]÷49
=[50-1]÷49
=49÷49
=1;
(2)−32×1.22÷0.32+(−
)2×(−3)3÷(−1)2007
=-9×1.44÷0.09+
×(-27)÷(-1)
=-144+3
=-141.
7 |
9 |
11 |
12 |
1 |
6 |
=[50-(28-33+6)]÷49
=[50-1]÷49
=49÷49
=1;
(2)−32×1.22÷0.32+(−
1 |
3 |
=-9×1.44÷0.09+
1 |
9 |
=-144+3
=-141.
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