早教吧作业答案频道 -->其他-->
A.accessB.passageC.wayD.approach的区别Thesystemhasbeendesignedtogivestudentsquickandeasytothedigitalesourcesofthelibrary.A.accessB.passageC.wayD.approach
题目详情
A. access B. passage C. way D. approach 的区别
The system has been designed to give students quick and easy___to the digital esources of the library.
A. access B. passage C. way D. approach
The system has been designed to give students quick and easy___to the digital esources of the library.
A. access B. passage C. way D. approach
▼优质解答
答案和解析
B
看了 A.accessB.pass...的网友还看了以下：
椭圆方程式的题椭圆方程x^2/a^2+y^2/b^2=t怎么用y=f(u),x=f(u)表示如果椭 2020-05-16 …
函数f(x)在(0,+∞)连续,f(1)=5/2,对所有x,t∈(0,+∞),满足∫(1,x)f( 2020-05-19 …
变限积分求道问题对函数f(t+h)-f(t-h)在[-h,h]上的积分对h求导.F(h)=∫[-h 2020-05-23 …
音标/su:/等于什么单词?搞错了！Sorry是/长腿f+u：t/ 2020-06-04 …
设f(x)=定积分(ln(1+t)/t)dt(x>0),上限x,下限1,求f(x)+f(1/x)设 2020-07-09 …
变上限积分区间0-x,F(x)=∫tf(x-t)dt将x-t=u,那变成区间还是0-x,∫（x-u 2020-07-10 …
复合函数求导时,为什么不能把中间变量直接带进去例如:y=(3x-1）^5,求导可以引入中间变量U= 2020-07-20 …
设函数y=f(x)处处二阶可导,对每个x有f’’(x)>=0,且u=u(t)为任意的一个连续函数, 2020-08-02 …
对于积分上限函数∫(a,t)f(y)dy,知道被积函数是f(t).那么对于∫(a,t)f(x+y) 2020-08-02 …
1.集合U={1，5}为全集，S包含于U，T包含于U，S交T={2}，S的补集交T={4}，S的补集 2020-12-08 …