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求m[f(x)]2nf(x)p=01.2(x3)2=x(x3)2.x22根号5x2=0ABBCCA=04n=150
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求m[f(x)]2 nf(x) p=01.2(x 3)2=x(x 3) 2.x22根号5x 2=0
AB BC CA=04n=150
AB BC CA=04n=150
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答案和解析
x^2/a^2 y^2/b^2=1中,SPF1F2=b^2*tanβ/2|x-1| |x-2|>0所以A={x|x2-3x 2=0}所以x^2/a^2 y^2/b^2=1中,SPF1F2=b^2*tanβ/2
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