3x-4/(x-2)(x-1)=a/x-1+b/x-2求整式a.b的值

Question

3x-4/(x-2)(x-1)=a/x-1+b/x-2求整式a.b的值

Answer 1

a/x-1+b/x-2
=[a(x-2)+b(x-1)]/(x-1)(x-2)
=(3x-4)/(x-1)(x-2)
a(x-2)+b(x-1)=3x-4
(a+b)x-(2a+b)=3a-4
所以a+b=3
2a+b=4
a=1,b=2