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函数y=2sin(-2x+π/3)的相位和初相分别是什么?变形得y=2sin(2x+2π/3)所以相位是2x+2π/3,初相是2π/3.是怎么变形的
题目详情
函数y=2sin(-2x+π/3)的相位和初相分别是什么?
变形得y=2sin(2x+2π/3)所以相位是2x+2π/3,初相是2π/3.
是怎么变形的
变形得y=2sin(2x+2π/3)所以相位是2x+2π/3,初相是2π/3.
是怎么变形的
▼优质解答
答案和解析
解函数y=2sin(-2x+π/3)
=-2sin(2x-π/3)
=-[-2sin(π+2x-π/3)]
=-[-2sin(2x+2π/3)]
=2sin(2x+2π/3)
=-2sin(2x-π/3)
=-[-2sin(π+2x-π/3)]
=-[-2sin(2x+2π/3)]
=2sin(2x+2π/3)
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