已知i为虚数单位,则i/(1-i)的虚部为?

Question

已知i为虚数单位,则i/(1-i)的虚部为?

Answer 1

i/(1-i)
=i(1+i)/(1-i)(1+i)
=(-1+i)/(1+1)
=-1/2+1/2·i
虚部为1/2·i