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已知角a的终边经过点p(4/5,-3/5).求sina的值
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已知角a的终边经过点p(4/5,-3/5).求sin a的值
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答案和解析
即sinα=3/5 /((4/5)²+(3/5)²)½=3/5
sin(π/2-α)/sin(α+π)*tan(α-π)/cos(3π-α)= cosα/(-sin α)*(-tan(π-α)/cosα)=-1/tanα*tanα/cosα
=-1/cosα
((4/5)²+(3/5)²)½=1,
-1/cosα=-1/((4/5)/1)=-5/4
sin(π/2-α)/sin(α+π)*tan(α-π)/cos(3π-α)= cosα/(-sin α)*(-tan(π-α)/cosα)=-1/tanα*tanα/cosα
=-1/cosα
((4/5)²+(3/5)²)½=1,
-1/cosα=-1/((4/5)/1)=-5/4
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