y=(x-3)^2/4(x-1)的导数是什么啊

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答案和解析

y = (1/4)(x-3)²(x-1)⁻¹
y' = (1/4)*2(x-3)(x-1)⁻¹ + (1/4)(x-3)²(-1)(x-1)⁻²
= (x-3)[2(x-1) - (x-3)]/[4(x-1)²]
= (x-3)(x+1)/[4(x-1)²]

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