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(-3x^3y^2+6x^4y^4-x^5y)/(-2/3x^2y)谢谢你们,已知分式方程（9/x-1）+1=1/x-1有增根,求a的值
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(-3x^3y^2+6x^4y^4-x^5y)/(-2/3x^2y)谢谢你们,已知分式方程（9/x-1）+1=1/x-1有增根,求a的值
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(-3x^3y^2+6x^4y^4-x^5y)/(-2/3x^2y)
=x^2y(-3xy+6x^2y^3-x^3)/(-2/3x^2y)
=(-3xy+6x^2y^3-x^3)/(-2/3)
=(-3xy+6x^2y^3-x^3)*(-3/2)
=(9xy-18x^2y^3+3x^3)/2
已知分式方程（9/x-1）+1=1/x-1有增根
求a的值
题目有误,a在何处?
=x^2y(-3xy+6x^2y^3-x^3)/(-2/3x^2y)
=(-3xy+6x^2y^3-x^3)/(-2/3)
=(-3xy+6x^2y^3-x^3)*(-3/2)
=(9xy-18x^2y^3+3x^3)/2
已知分式方程（9/x-1）+1=1/x-1有增根
求a的值
题目有误,a在何处?
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