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y'+2xy=x通解
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y'+2xy=x通解
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y'=x-2xy; dy/dx=x(1-2y); dy/(1-2y) = xdx; ∫dy/(1-2y) = ∫xdx; -1/2ln|1-2y| = 1/2x^2+C; ln|1-2y| = -x^2+C1; 1-2y = C2e^(-x^2);///C2是某一常数,绝对值可以直接去掉/// y = C3e^(-x^2) + 1/2;///C3=-1/2C2///
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