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证明:∫(sinx/x)dx=∫dx/arccosx.左边上限派/2,下限派/3;右边上限1/2,下限0.没分了,请见谅!
题目详情
证明:∫ (sinx / x )dx=∫ dx/arccosx.左边上限派/2,下限派/3;右边上限1/2,下限0.
没分了,请见谅!
没分了,请见谅!
▼优质解答
答案和解析
右边作变换t=arccosx,则x=cost,dx=-sintdt.
x=0时,t=π/2,x=1/2时,t=π/3
所以,
∫(0→1/2) dx/arccosx
=∫(π/2→π/3) (-sint)dt/t
=∫(π/3→π/2) (sint/t) dt
证毕!
x=0时,t=π/2,x=1/2时,t=π/3
所以,
∫(0→1/2) dx/arccosx
=∫(π/2→π/3) (-sint)dt/t
=∫(π/3→π/2) (sint/t) dt
证毕!
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