帮我解一下这个三角函数题y=sin(π/6-2x)(x属于闭区间0,π闭区间）为增函数的区间是答案闭区间三分之π到六分之五π闭区间最好解释的清楚些…………

Question

帮我解一下这个三角函数题
y=sin(π/6-2x)(x属于闭区间0,π闭区间）为增函数的区间是
答案闭区间三分之π到六分之五π闭区间
最好解释的清楚些…………

Answer 1

0<=x<=π
-2π<=-2x<=0
-11π/6<=π/6-2x<=π/6
因为y=sinx则增区间是[2kπ-π/2,2kπ+π/2]
则在-11π/6<=π/6-2x<=π/6中符合的有
-π/2<=π/6-2x<=π/6
-2π/3<=-2x<=0
所以0<=x<=π/3
你的答案不对吧