已知函数y=sin2x+根号3cos2x1）化成y化成Asin(wx+∞）形式2）五点画法,取那五点

Question

已知函数y=sin2x+根号3cos2x
1）化成y化成Asin(wx+∞）形式
2）五点画法,取那五点

Answer 1

y=2sin(2x+π/3)
所以2x+π/3=0,π/2,π,3π/2,2π
所以是(-π/6,0)
(π/12,1)
(π/3,0)
(7π/12,-1)
(5π/6,0)