求值tan(kπ+π/6)cos(kπ-4π/3),k属于z

Question

求值tan(kπ+π/6)cos(kπ-4π/3),k属于z

Answer 1

当k=2n时（n属于z）,原式=tan（π/6）cos(-4π/3)=-√3/6;
当k=2n+1时(n属于z),原式=-tan（π/6）cos(-4π/3)=√3/6;