解分式方程x/(x-1)-2/x=1(2x^2-8x+16)/(x^2-4x+4)=2x/(-x-2)

Question

解分式方程
x/(x-1)-2/x=1
(2x^2-8x+16)/(x^2-4x+4)=2x/(-x-2)

Answer 1

1：通分：[x^2-2(x-1)]/[x*(x-1)]=1
整理：x^2-2(x-1)-x(x-1)=0
解得：x=2
2：没这么麻烦吧,题抄错了吧?