求以下题目的算法或思路吧依据给定值，求解下面方程x的近似计算解。ai＝a[i]，m为a[0]-a[n]的平均值。a[92]={74,72,69,62,64,61,74,70,64,74,46,82,60,86,70,67,70,68,60,65,62,73,60,60,80,71,68,60,81,60,74,70,55,76,88,5

Question

求以下题目的算法或思路吧依据给定值，求解下面方程x的近似计算解。a i＝a[i]，m为a[0]-a[n]的平均值。 a[92]={74,72,69,62,64,61,74,70,64,74,46,82,60,86,70,67,70,68,60, 65,62,73,60,60,80,71,68,60,81,60,74,70,55,76,88,51,82,68,80,63,65, 47,72,62,60,68,81,43,60,69,76,72,72,68,68,60,75,40,60,78,82,75,67, 60,60,95,69,65,64,60,60,64,62,72,66,42,74,71,81,70,77,63,69,41,65, 69,73,60,69,80,81,75}

Answer 1

说说我的思路啊。。。不一定对啊。。。 可能是先把a排序，然后计算b[i]=a[i]-a[0] (n>=i>=0) // 因为求和是0，所以每项除以 x^min(a[i])之后结果依然是0 设c[i]=a[i]-m; 之后的表达式应该是 sum(c[i]*x^b[i]) 然后用牛顿法求一元多项式