早教吧作业答案频道 -->数学-->
(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)怎么算!
题目详情
(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)
怎么算!
怎么算!
▼优质解答
答案和解析
(2x^3y^3-2x^3y+1/8^4+y)/(-1/2x^3y)=-2(2x^3y^3-2x^3y+1/8^4+y)/(x^3y)=-2(2y^2-2)+2(1/8^4+y)/(x^3y)=-4y^2-4+2/8^4(x^3y)+2y/(x^3y)=-4y^2-4+2/2^12(x^3y)+2/x^3=-4y^2-4+1/2^11x^3y+2/x^3
看了 (2x^3y^3-2x^3y...的网友还看了以下：