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计算:(1)(-7i+5)-(9-8i)+(3-2i);(2)(4+i)(6-2i)+(7-i)(4-3i);(3)2+2ii+1+i1-i.
题目详情
计算:
(1)(-7i+5)-(9-8i)+(3-2i);
(2)(4+i)(6-2i)+(7-i)(4-3i);
(3)
+
.
(1)(-7i+5)-(9-8i)+(3-2i);
(2)(4+i)(6-2i)+(7-i)(4-3i);
(3)
2+2i |
i |
1+i |
1-i |
▼优质解答
答案和解析
(1)(-7i+5)-(9-8i)+(3-2i)
=(5-9+3)+(-7+8-2)=-1-i;
(2)(4+i)(6-2i)+(7-i)(4-3i)
=24-2i2-2i+28+3i2-25i
=51-27i;
(3)
+
=
+
=
+
=2-2i+i=2-i
=(5-9+3)+(-7+8-2)=-1-i;
(2)(4+i)(6-2i)+(7-i)(4-3i)
=24-2i2-2i+28+3i2-25i
=51-27i;
(3)
2+2i |
i |
1+i |
1-i |
(2+2i)i |
i2 |
(1+i)2 |
(1-i)(1+i) |
2i-2 |
-1 |
2i |
2 |
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