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cos(π/9)*cos(2π/9)*cos(3π/9)*cos(4π/9)结果不重要
题目详情
cos(π/9)*cos(2π/9)*cos(3π/9)*cos(4π/9)
结果不重要
结果不重要
▼优质解答
答案和解析
=sin(π/9)*cos(π/9)*cos(2π/9)*cos(3π/9)*cos(4π/9)/sin(π/9)
=sin(2π/9)cos(2π/9)*cos(3π/9)*cos(4π/9)/[2*sin(π/9)]
=sin(4π/9)*cos(3π/9)*cos(4π/9)/[4*sin(π/9)]
=sin(8π/9)*cos(3π/9)/[8*sin(π/9)]
=sin(π/9)*cos(3π/9)/[8*sin(π/9)]
=cos(3π/9)/8
=1/16
=sin(2π/9)cos(2π/9)*cos(3π/9)*cos(4π/9)/[2*sin(π/9)]
=sin(4π/9)*cos(3π/9)*cos(4π/9)/[4*sin(π/9)]
=sin(8π/9)*cos(3π/9)/[8*sin(π/9)]
=sin(π/9)*cos(3π/9)/[8*sin(π/9)]
=cos(3π/9)/8
=1/16
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