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limx→1(x^3+x^2-5x-3)/(x^3-4x^2+5x-2)求极限.
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lim x→1 (x^3+x^2-5x-3)/(x^3-4x^2+5x-2) 求极限.
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答案和解析
分子应该是x^3+x^2-5x+3才是不定式
lim x→1 (x^3+x^2-5x+3)/(x^3-4x^2+5x-2)
=lim x→1 [(x+3)(x-1)^2] / [(x+1)(x-1)(x-2)]
=lim x→1 [(x+3)(x-1)] / [(x+1)(x-2)]
= 0
lim x→1 (x^3+x^2-5x+3)/(x^3-4x^2+5x-2)
=lim x→1 [(x+3)(x-1)^2] / [(x+1)(x-1)(x-2)]
=lim x→1 [(x+3)(x-1)] / [(x+1)(x-2)]
= 0
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