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设X:Y:Z=2:3:5,且满足3X-3Y+Z=4,求2X+3Y-4Z
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设X:Y:Z=2:3:5,且满足3X-3Y+Z=4,求2X+3Y-4Z
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答案和解析
由X:Y:Z=2:3:5
设X=2t,Y=3t,Z=5t
代入3X-3Y+Z=4,
得 6t-9t+5t=4
2t=4
t=2
所以X=4,Y=6,Z=10
故2X+3Y-4Z
=2×4+3×6-4×10
=8+18-40
=-14
答案:-14
设X=2t,Y=3t,Z=5t
代入3X-3Y+Z=4,
得 6t-9t+5t=4
2t=4
t=2
所以X=4,Y=6,Z=10
故2X+3Y-4Z
=2×4+3×6-4×10
=8+18-40
=-14
答案:-14
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