[(x+y)^2-(x-y)^2]/(2xy)=?(x+2)^2-(x+2)(x-2)=?(-0.5)^-4-1+0.2^2006*5^2005=?(3x+2y)*(4x-5y)-11(x+y)(x-y)+?(-2y^2)^4/(y^2)^2=?(4a^3b-6a^3b^2-10ab^2)/(2ab)=?(-2x+y)(y-2x)-(2x+y)^2=?-4+[0.75(5+4^4)-(15)^2]-(-1/3)^2005*3^2006

Question

[(x+y)^2-(x-y)^2]/(2xy)=?
(x+2)^2-(x+2)(x-2)=?
(-0.5)^-4 -1+0.2^2006*5^2005=?
(3x+2y)*(4x-5y)-11(x+y)(x-y)+?
(-2y^2)^4/(y^2)^2=?
(4a^3b-6a^3b^2-10ab^2)/(2ab)=?
(-2x+y)(y-2x)-(2x+y)^2=?
-4+[0.75(5+4^4)-(15)^2]-(-1/3)^2005*3^2006

Answer 1

你应该自己算阿,这是练习!
8x^2y^2
4x+4
16/15
x^2-7xy+y^2
16y^4
2a^2-3a^2b-5b
-8xy
-121/4
没检查