早教吧作业答案频道 -->数学-->
(x-y/2)^2-(x+y/2)^2,其中X,Y互为相反数（先分解因式,再计算求值）
题目详情
(x-y/2)^2-(x+y/2)^2,其中X,Y互为相反数（先分解因式,再计算求值）
▼优质解答
答案和解析
x、y应该是互为倒数吧
(x-y/2)^2-(x+y/2)^2
=[(x-y/2)-(x+y/2)][(x-y/2)+(x+y/2)]
=(x-y/2-x-y/2)(x-y/2+x+y/2)
=(-y)*2x
=-2xy
=-2*1
=-2
(x-y/2)^2-(x+y/2)^2
=[(x-y/2)-(x+y/2)][(x-y/2)+(x+y/2)]
=(x-y/2-x-y/2)(x-y/2+x+y/2)
=(-y)*2x
=-2xy
=-2*1
=-2
看了(x-y/2)^2-(x+y/...的网友还看了以下：