定义一种新运算“△”：x△y=1/xy+1/(x+1)+1/(y+m),已知2△1=4/31,求m的值2,求2007△2008的值

Question

定义一种新运算“△”：x△y=1/xy + 1/(x+1)+ 1/(y+m),已知2△1=4/3
1,求m的值
2,求2007△2008的值

Answer 1

1 m=1
2 1/2007+1/2009