早教吧作业答案频道 -->英语-->
python英文题目求解答!~~~~Givendictionaries,d1andd2,createanewdictionarywiththefollowingproperty:foreachentry(a,b)ind1,ifaisnotakeyofd2(i.e.,notaind2)thenadd(a,b)tothenewdictionaryforeachentry(a,b)in
题目详情
python英文题目求解答!~~~~
Given dictionaries, d1 and d2, create a new dictionary with the following property: for each entry (a, b) in d1, if a is not a key of d2 (i.e., not a in d2) then add (a,b) to the new dictionary for each entry (a, b) in d2, if a is not a key of d1 (i.e., not a in d1) then add (a,b) to the new dictionary
For example, if d1 is {2:3, 8:19, 6:4, 5:12} and d2 is {2:5, 4:3, 3:9}, then the new dictionary should be {8:19, 6:4, 5:12, 4:3, 3:9}
Associate the new dictionary with the variable d3
Given dictionaries, d1 and d2, create a new dictionary with the following property: for each entry (a, b) in d1, if a is not a key of d2 (i.e., not a in d2) then add (a,b) to the new dictionary for each entry (a, b) in d2, if a is not a key of d1 (i.e., not a in d1) then add (a,b) to the new dictionary
For example, if d1 is {2:3, 8:19, 6:4, 5:12} and d2 is {2:5, 4:3, 3:9}, then the new dictionary should be {8:19, 6:4, 5:12, 4:3, 3:9}
Associate the new dictionary with the variable d3
▼优质解答
答案和解析
def new_dict(dict1, dict2): newdict = {} newdict.update(dict1) newdict.update(dict2) d = newdict.copy() for i in d.iterkeys(): if dict1.has_key(i) and dict2.has_key(i): ...
看了python英文题目求解答!~...的网友还看了以下:
高一化学一道求中子数数目的基础题目》》》某元素原子的质量数为A,它的离子X(n+),(n+)为X的 2020-05-24 …
定积分的应用里面有一个是求沿着Y轴旋转的曲线的体积老师给了两个公式一个是V=∫[ab]π*f(y) 2020-06-10 …
椭圆直线斜率今天做题目看椭圆解析有点不懂题目是这样的,椭圆x²/a²+y²/b²(a>b>0)上顶 2020-06-30 …
这是一道数理统计与概率论的题目,题目是这样的:设P{X=k}=(1/2)^k,k=1,2,3.,又 2020-07-13 …
指数运算的问题-=、a,b,c都是正数,且至少有一个不为1,a^x*b^y*c^z=a^y*b^z 2020-07-22 …
我想问二模的一道数学题!函数y=2x(x∈R)的反函数为A.y=log2x(x>0)B.y=log 2020-07-30 …
几道关于集合的题目十万火急的拉```~小女子在这求1已知U={(x,y)|x∈R,y∈R},A={ 2020-07-30 …
求两条关于集合的题目的解法1,若集合A=(y|y=x平方+2x+4,x属于实数),B=(y|y=a 2020-07-30 …
集合的题目、明天要交的、坐等.设由4的整数倍再加上2的所有实数构成的集合为A,由4的整数倍再加3的 2020-08-02 …
关于根号的题目已知根号(a(x-a))+根号(a(y-a))=根号(x-a)-根号(a-y)成立,a 2020-12-31 …