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(2012•东莞模拟)计算下列各题.5025-2940÷28×3745÷((35−14)÷710)4.8×45+6.2÷114-0.8.

题目详情
(2012•东莞模拟)计算下列各题.
5025-2940÷28×37                            
 
4
5
÷((
3
5
1
4
7
10
)     
4.8×
4
5
+6.2÷1
1
4
-0.8.
▼优质解答
答案和解析
(1)5025-2940÷28×37,
=5025-105×37,
=5025-3885,
=1140;

(2)
4
5
÷[(
3
5
-
1
4
)÷
7
10
],
=
4
5
÷[
7
20
÷
7
10
],
=
4
5
÷[
7
20
×
10
7
],
=
4
5
÷
1
2

=
4
5
×2,
=
8
5


(3)4.8×
4
5
+6.2÷1
1
4
-0.8,
=4.8×
4
5
+6.2×
4
5
-0.8,
=4.8×0.8+6.2×0.8-0.8,
=(4.8+6.2-1)×0.8,
=10×0.8,
=8.