偏导数.急设z=(e^u)sinv而u=xy,v=x+y求dz/dx,dz/dy

Answer 1

dz/dx 是z对x的偏导,这样把u,v都带入的话直接球偏导就好了
dz/dx=y*e^(xy)*sin(x+y)+e^(xy)*cos(x+y)
同理也可得到
dz/dy=x*e^(xy)*sin(x+y)+e^(xy)*cos(x+y)