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求sinx+cosx/sinx-cosx的最小正周期
题目详情
求sinx+cosx/sinx-cosx的最小正周期
▼优质解答
答案和解析
(sinx+cosx)/(sinx-cosx)
=√2【sinxcos(π/4)+cosxsin(π/4)】/√2【sinxsin(π/4)-cosxcos(π/4)】
=sin(x+π/4)/【-cos(x+π/4)】
=-tan(x+π/4)
最小正周期是T=π/1=π
=√2【sinxcos(π/4)+cosxsin(π/4)】/√2【sinxsin(π/4)-cosxcos(π/4)】
=sin(x+π/4)/【-cos(x+π/4)】
=-tan(x+π/4)
最小正周期是T=π/1=π
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