函数y=√3sinx+cosx,x∈[-π/2,π/2]的最大值是

Question

函数y=√3sinx+cosx,x∈[-π/2,π/2]的最大值是

Answer 1

y=√3sinx+cosx
=2sin(x+π/6)
x∈[-π/2,π/2]
x+π/6∈[-π/3,2π/3]
所以函数的最大值是2,最小值是-√3