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(用递等式计算,写出必要的计算过程,能简则简)(1÷0.5+0.5÷1)×0.140.4×0.4×1.5×2.56.38×99+6.38(200-195.2)÷(8.37+1.23)×0.5[5.4÷18+(41.47+38.53)×0.1]÷2.5

题目详情
(用递等式计算,写出必要的计算过程,能简则简)
(1÷0.5+0.5÷1)×0.14             
0.4×0.4×1.5×2.5
6.38×99+6.38 (200-195.2)÷(8.37+1.23)×0.5
[5.4÷18+(41.47+38.53)×0.1]÷2.5
▼优质解答
答案和解析
(1)(1÷0.5+0.5÷1)×0.14
=(2+0.5)×0.14
=2.5×0.14
=0.35;

(2)0.4×0.4×1.5×2.5
=(0.4×1.5)×(0.4×2.5)
=0.6×1
=0.6;

(3)6.38×99+6.38
=6.38×(99+1)
=6.38×100
=638;

(4)(200-195.2)÷(8.37+1.23)×0.5
=4.8÷9.6×0.5
=0.5×0.5
=0.25;

(5)[5.4÷18+(41.47+38.53)×0.1]÷2.5
=[5.4÷18+80×0.1]÷2.5
=[0.3+8]÷2.5
=8.3÷2.5
=3.32.