早教吧作业答案频道 -->英语-->
英语翻译BybirthandbyeducationJeffersonbelongedtothehighestsocialclass.Yet,inadaywhenfewnoblepersonseverspoketothoseofhumbleoriginsexcepttogiveanorder,Jeffersonwentoutofhiswaytotalkwithgradeners,servants,andw
题目详情
英语翻译
By birth and by education Jefferson belonged to the highest social class.Yet,in a day when few noble persons ever spoke to those of humble origins except to give an order,Jefferson went out of his way to talk with gradeners,servants,and waiters.
要准确,要真心!
By birth and by education Jefferson belonged to the highest social class.Yet,in a day when few noble persons ever spoke to those of humble origins except to give an order,Jefferson went out of his way to talk with gradeners,servants,and waiters.
要准确,要真心!
▼优质解答
答案和解析
参考如下
无论是从出身还是从教育上来讲,杰弗森都属于最上流的社会阶层.但是,在一个鲜有贵族跟出身卑微者说话的年代,杰弗森却摒弃阶层偏见,去跟园丁、仆人和招待们对话.
无论是从出身还是从教育上来讲,杰弗森都属于最上流的社会阶层.但是,在一个鲜有贵族跟出身卑微者说话的年代,杰弗森却摒弃阶层偏见,去跟园丁、仆人和招待们对话.
看了英语翻译Bybirthandb...的网友还看了以下：
n阶方阵A对任意n维向量x,满足x^TAx=0,充要条件为AT=-A；证明：充分性：f=x^TAx 2020-05-17 …
高数题目设f(x)在[a,b]上可导,又f'(x)+[f(x)]^2-∫(a到x)f(t)dt=0 2020-06-12 …
设f(x)为连续函数,f(0)=a,F(t)=∫∫∫Ω{z-f(x^2+y^2+z^2)]dv,其 2020-06-15 …
针对程序段：IF（A||B||C）THENW=W/X,对于(A,B,C)的取值,（57）测试用例能 2020-07-10 …
若f(x+a)是偶函数.则另t=x+a则f（t）是偶函数,则f（t）=f（-t）则f（x+a）=f 2020-08-01 …
对于积分上限函数∫(a,t)f(y)dy,知道被积函数是f(t).那么对于∫(a,t)f(x+y) 2020-08-02 …
（2012•湛江一模）已知函数f（x）的图象在[a，b]上连续不断曲线，定义：f1（x）=min{f 2020-11-12 …
已知二次函数f(x)满足发f(x+1)-f(x)=2x(x属于R）,且f(0）=1,设g(t)=f( 2020-12-08 …
英语翻译a:振幅时间（a-t）曲线上升后变平.Swingtime(a-t)b:振幅时间（a-t）曲线 2020-12-31 …
设A为实数,记函数f(x)=a√(1-x^2)+√(1+x)+√(1-x)的最大值为g(a)1.设t 2020-12-31 …