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化简:cos(θ+π2)sin(θ+3π)sin(θ−π2)cos(θ−2π)tan(θ+π)=.

题目详情
化简:
cos(θ+
π
2
)sin(θ+3π)
sin(θ−
π
2
)cos(θ−2π)tan(θ+π)
=______.
▼优质解答
答案和解析
cos(θ+
π
2
)sin(θ+3π)
sin(θ−
π
2
)cos(θ−2π)tan(θ+π)
=
sinθsinθ
−cosθcosθtanθ
=
sinθsinθcosθ
−cosθcosθsinθ
=-tanθ.
故答案为:-tanθ.