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a=-1/6 b=3/2 3a+b/3a-b-3a-b/3a+b/[1/(1-b/3a)]/(1-2b/3a+b)=?
题目详情
a=-1/6 b=3/2 3a+b/3a-b-3a-b/3a+b/[1/(1-b/3a)]/(1-2b/3a+b)=?
▼优质解答
答案和解析
3a+b/3a-b-3a-b/3a+b/[1/(1-b/3a)]/(1-2b/3a+b)
=(3a-3a)+(b/3a-b/3a)-b+b*(1-b/3a)/(1-2b/3a+b)
=-b+(1-1/3a)/(1/b-2/3a+1)
=-3/2+(1+2)/(2/3+4+1)
=-3/2+9/17
=-33/34
=(3a-3a)+(b/3a-b/3a)-b+b*(1-b/3a)/(1-2b/3a+b)
=-b+(1-1/3a)/(1/b-2/3a+1)
=-3/2+(1+2)/(2/3+4+1)
=-3/2+9/17
=-33/34
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