tanx-x/（x^2）*sinx当x趋向0时 求极限?

Question

tanx-x/（x^2）*sinx当x趋向0时 求极限?

Answer 1

1.(tanx-x)/(x^2*sinx)=(tanx-x)/x^3=(罗比达)[(secx)^-1]/3x^2=(tanx)^2/3x^2=1/3
2.tanx-x用泰勒展开 方法同上