轮船在大海上航行,船的吃水深度为5米,若船底有一条长20cm.宽为5cm的隙缝,船员需要用多大的力才能堵住涌进船舱的海水已知海水密度1.1g/cm3

Question

轮船在大海上航行,船的吃水深度为5米,若船底有一条长20cm.宽为5cm的隙缝,船员需要用多大的力才能堵住涌进船舱的海水已知海水密度1.1g/cm3

Answer 1

P=F/S=ρgh ==> F= Sρgh
F=(20cmx5cm) x 1.1g/cm3 x 9.8N/Kg x 5m
=100cm2 x 1.1g/cm3 x 9.8N/Kg x 500cm
= 100 x 1.1g/cm x 9.8N/Kg x 500cm
= 110g x 9.8N/Kg x 500
= 11000g x 9.8N/Kg x 5
= 11Kg x 9.8N/Kg x 5
= 11 x 9.8N x 5
= 593N