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sin(π-θ）+cos(2π-θ）/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=______
题目详情
sin(π-θ）+cos(2π-θ）/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=______
▼优质解答
答案和解析
[sin(π-θ)+cos(2π-θ)]/[cos(5π/2-θ)+sin(3π/2+θ)]=2=(sinθ+cosθ)/(sinθ-cosθ)=2
sinθ=3cosθ
tanθ=3
sinθ*cosθ=sinθcosθ/[sin^θ+cos^θ]=tanθ/[tan^θ+1]=3/10
sinθ=3cosθ
tanθ=3
sinθ*cosθ=sinθcosθ/[sin^θ+cos^θ]=tanθ/[tan^θ+1]=3/10
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