早教吧作业答案频道 -->数学-->
1/(x^2+2x-3)+18/(x^2+2x+2)=18/(x^2+2x+1)解方程.
题目详情
1/(x^2+2x-3)+18/(x^2+2x+2)=18/(x^2+2x+1)
解方程.
解方程.
▼优质解答
答案和解析
设y=（x+1）^2
1/(y-4)+18/(y+1)=18/y
y^2+y+18(y^2-4y)=18(y^2-3y-4)
y^2-17y+72=0
y=8或9
y=8时,x+1=±2√2,x=-1=±2√2
y=9时,x+1==±3,x=2或-4
1/(y-4)+18/(y+1)=18/y
y^2+y+18(y^2-4y)=18(y^2-3y-4)
y^2-17y+72=0
y=8或9
y=8时,x+1=±2√2,x=-1=±2√2
y=9时,x+1==±3,x=2或-4
看了 1/(x^2+2x-3)+1...的网友还看了以下：