求人帮忙算2个值域急要y=(x^2-2x+2)/(x^2+1)其中X是实数y=(x^2-2x+1)/(x+1)x大于等于1/2小于等于2/3

Question

求人帮忙算2个值域 急要
y=(x^2-2x+2)/(x^2+1) 其中X是实数
y=(x^2-2x+1)/(x+1) x大于等于1/2 小于等于2/3

Answer 1

1:y=(x^2-2x+2)/(x^2+1)=1+(1-2x)/(x^2+1)
x>0增大时,分母单调递增,分子单调递减,(1-2x)/(x^2+1)单调递减
x