(1).2x^2-3x+1=0 (2).x^2-2倍根号3x+3=0 (3).3x^2-1=4x (4).2倍根号3x-根号2（x^2+1)=0用公式法怎么解

Question

(1).2x^2-3x+1=0 (2).x^2-2倍根号3x+3=0 (3).3x^2-1=4x (4).2倍根号3x-根号2（x^2+1)=0用公式法怎么解

Answer 1

2x^2-3x+1=0
(2x-1)(x-1)=0
x=1/2或x=1
x^2-2√3x+3=0
x^2-2√3x+(√3)^2=0
(x-√3)^2=0
x=√3
3x^2-1=4x
3x^2-4x-1=0
x^2-4x/3-1/3=0
x^2-4x/3+4/9-4/9-1/3=0=0
(x-2/3)^2-7/9=0
(x-2/3-√7/3)(x-2/3+√7/3)=0
x=2/3+√7/3或x=2/3-√7/3
2√3x-√2（x^2+1)=0
2√3x=√2（x^2+1)
12x^2=2（x^2+1)
12x^2=2x^2+2
10x^2=2
x^2=1/5
x=±√5/5