y=sin(x-π/6)sin(x+π/3)最小正周期

题目详情

▼优质解答

答案和解析

y=sin(x-π/6)sin(x+π/3)
=-cos(x-π/6+π/2)sin(x+π/3)
=-cos(x+π/3)sin(x+π/3)
=-sin(2x+2π/3)/2
T=2π/2=π

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