早教吧作业答案频道 -->数学-->
设α为锐角,若cos(α+π/6)=4/5,则sin(2α+π/12)=?
题目详情
设α为锐角,若cos(α+π/6)=4/5,则sin(2α+π/12)=?
▼优质解答
答案和解析
α∈(0,π/2)
α+π/6∈(π/6,2π/3)
cos(α+π/6)=4/5>0
∴α+π/6∈(π/6,π/2)
∴2α+π/3∈(π/3,π)
cos(2α+π/3)
=2cos²(α+π/6)-1
=2*(4/5)²-1
=32/25-1
=7/25>0
∴2α+π/3∈(π/3,π/2)
sin(2α+π/3)=24/25
sin(2α+π/12)
=sin(2α+π/3-π/4)
=sin(2α+π/3)cosπ/4-cos(2α+π/3)sinπ/4
=24/25*√2/2-7/25*√2/2
=24√2/50-7√2/50
=17√2/50
α+π/6∈(π/6,2π/3)
cos(α+π/6)=4/5>0
∴α+π/6∈(π/6,π/2)
∴2α+π/3∈(π/3,π)
cos(2α+π/3)
=2cos²(α+π/6)-1
=2*(4/5)²-1
=32/25-1
=7/25>0
∴2α+π/3∈(π/3,π/2)
sin(2α+π/3)=24/25
sin(2α+π/12)
=sin(2α+π/3-π/4)
=sin(2α+π/3)cosπ/4-cos(2α+π/3)sinπ/4
=24/25*√2/2-7/25*√2/2
=24√2/50-7√2/50
=17√2/50
看了 设α为锐角,若cos(α+π...的网友还看了以下:
如图所示,梯形ABCD中,AD∥BC,对角线AC,BD相交于点O,若S△AOD:S△ACD=1:3 2020-04-05 …
向量组α1,α2,α3.αs线性无关的充要条件是A.α1,α2,α3.αs均不是零向量B.α1,α 2020-05-16 …
求函数的拉氏反变换:X(s)=(s+2)/[s·(s+1)^2·(s+3)]我的解法如下:X(s) 2020-05-22 …
(2)“锐不可当”的问题?1).“锐不可当”和“锐不可挡”都是词语吗?2).“锐不可当”的“当”的 2020-06-26 …
已知传递函数 G(S)=6s2+1/s3+3s2+3s=1 H(S)=(s+1)(s+2)/(s+ 2020-06-27 …
设向量组(Ⅰ)α1,α2,…αs的秩为r1,向量组(Ⅱ)β1,β2,…βs的秩为r2,且向量组(Ⅰ 2020-06-30 …
(2007•呼伦贝尔)锐角三角形的三个内角是∠A,∠B,∠C,如果α=∠A+∠B,β=∠B+∠C, 2020-07-21 …
设实数集S是满足下面两个条件的集合:①:1不属于S;②:若a∈S,则1/(1-a)∈S求证:若a∈ 2020-07-30 …
正弦定理1、在三角形ABC中,A大于B,则cos2Acos2B(大于、小于、等于)为什么?2、在锐 2020-08-02 …
设实数集S是满足下面两个条件的集合:①1∉S;②若a∈S则1/1-a∈S(1),求证:若a∈S,则1 2020-12-01 …