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aboutmagneticfluxAloudspeakermagnethasacircularair-gapofinnerdiameterd1=22mm,outerdiameterd2=24mm,anddepthh=8mmtoaccommodatetheoscillationcoil.Iftheair-gaphasmagneticfluxdensityB=0.75Wb/m2,findthemagneticfluxthatmus
题目详情
about magnetic flux
A loudspeaker magnet has a circular air-gap of inner diameter d1=22mm,outer diameter d2=24mm ,and depth h=8mm to accommodate the oscillation coil.If the air-gap has magnetic flux density B=0.75Wb/m2 ,find the magnetic flux that must be produced for a flux leakage of 15%.
498.6μWb
我不理解题意 答案绝对没错
A loudspeaker magnet has a circular air-gap of inner diameter d1=22mm,outer diameter d2=24mm ,and depth h=8mm to accommodate the oscillation coil.If the air-gap has magnetic flux density B=0.75Wb/m2 ,find the magnetic flux that must be produced for a flux leakage of 15%.
498.6μWb
我不理解题意 答案绝对没错
▼优质解答
答案和解析
扬声器磁体有一个圆形气隙内径蛋白D1 = 22毫米,外径D2类= 24毫米,和深度h = 8毫米,以适应振荡线圈.如果气隙的磁通密度乙= 0.75Wb/m2 ,找到磁通量必须制作的漏磁的15 ％ .
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