0.1mol/l某一元酸HA在水中有0.1%发生电离,HA的电离平衡常数约为1*10^-7怎么求的

Question

0.1mol/l某一元酸HA在水中有0.1%发生电离,HA的电离平衡常数约为1*10^-7 怎么求的

Answer 1

.HA ========Ｈ＋ ＋A- 初...0.1mol/L .0.0 转,0.1*0.1%.,0.1*0.1%,,0.1*0.1% 平...0.1-0.1*0.1%...0.1*0.1% ..0.1*0.1% K =0.1*0.1% *0.1*0.1%/(0.1-0.1*0.1%.)=1*10^-7